Difference between revisions of "User:Msf24"

Revision as of 03:39, 30 December 2009

Work to see how fast one must pull on toilet paper to get it to tear:

let \(f\) be the force required to tear it

let \(M\) be the Mass of the toilet paper roll

let \(I\) be the rotational inertia of the roll \(I\)= \(\frac{1}{2}(M)(R)^2\)

And let \(\tao\)be the torque

Variations/Modifications:

You could require the students to derive \(I\)

You could require the students to calculate \(M\) given information about the dimensions and how heavy some toilet paper is

@@ Line 5: / Line 5: @@
 let <math>M</math> be the Mass of the toilet paper roll
-let <math>I</math> be the rotational inertia of the roll ( = <math>\frac{1}{2}(M)(R)^2</math>)
+let <math>I</math> be the rotational inertia of the roll  <math>I</math>= <math>\frac{1}{2}(M)(R)^2</math>
+And let <math>\tao</math>be the torque